[A] assignment
[B] temptation
[C] attempt
[D] commission
第1题:
A.super(name,baseSalary);
B.this.commission=commission;
C.super();this.commission=commission;
D.this.commission=commission;super();
E.super(name,baseSalary);this.commission=commission;
F.this.commission=commission;super(name,baseSalary);
G.super(name,baseSalary,commission);
第2题:
1.publicclassEmployee{2.Stringname;3.doublebaseSalary;4.Employee(Stringname,doublebaseSalary){5.this.name=name;6.this.baseSalary=baseSalary;7.}8.}And:1.publicclassSalespersonextendsEmployee{2.doublecommission;3.publicSalesperson(Stringname,doublebaseSalary,4.doublecommission){5.//insertcodehere6.}7.}Whichcode,insertedatline7,completestheSalespersonconstructor?()
A.this.commission=commission;
B.superb();commission=commission;
C.this.commission=commission;superb();
D.super(name,baseSalary);this.commission=commission;
E.super();this.commission=commission;
F.this.commission=commission;super(name,baseSalary);
第3题:
The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? ()
A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;
B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;
C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;
D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
第4题:
Click the Exhibit button and examine the data from the EMP table.The COMMISSION column shows the monthly commission earned by the employee.Which two tasks would require subqueries or joins in order to be performed in a single step? ()
A.listing the employees who earn the same amount of commission as employee 3
B.finding the total commission earned by the employees in department 10
C.finding the number of employees who earn a commission that is higher than the average commission of the company
D.listing the departments whose average commission is more than 600
E.listing the employees who do not earn commission and who are working for department 20 in descending order of the employee ID
F.listing the employees whose annual commission is more than 6000
第5题:
第6题:
哪种情况需要Mannual Commission基站?()
第7题:
业务信道分配请求次数统计点是()消息
第8题:
寻呼响应次数统计点是()消息
第9题:
The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? ()
第10题:
Examine the data from the EMP table: EMP_ID DEPT_ID COMMISSION 1 10 500 2 20 1000 3 10 4 10 600 5 30 800 6 30 200 7 10 8 20 300 The COMMISSION column shows the monthly commission earned by the employee. Which three tasks would require subqueries or joins in order to perform in a single step? ()
第11题:
Deleting the records of employees who do not earn commission.
Increasing the commission of employee 3 by the average commission earned in department 20.
Finding the number of employees who do NOT earn commission and are working for department 20.
Inserting into the table a new employee 10 who works for department 20 and earns a commission that is equal to the commission earned by employee 3.
Creating a table called COMMISSION that has the same structure and data as the columns EMP_ID and COMMISSIONS of the EMP table.
Decreasing the commission by 150 for the employees who are working in department 30 and earning a commission of more then 800.
第12题:
super(name, baseSalary);
this.commission = commission;
super();this.commission = commission;
this.commission = commission;super();
super(name, baseSalary);this.commission = commission;
this.commission = commission;super(name, baseSalary);
super(name, baseSalary, commission);
第13题:
A.RAB ASSIGNMENT REQUEST之后;
B.RAB ASSIGNMENT RESPONSE之前;
C.RAB ASSIGNMENT REQUEST之前;
D.RAB ASSIGNMENT RESPONSE之后。
第14题:
The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? ()
A. All of the desired results
B. Two of the desired results
C. One of the desired results
D. An error statement
第15题:
Examine the data from the EMP table:The COMMISSION column shows the monthly commission earned by the employee.Which three tasks would require subqueries or joins in order to perform in a single step?()
A. Deleting the records of employees who do not earn commission.
B. Increasing the commission of employee 3 by the average commission earned in department 20.
C. Finding the number of employees who do NOT earn commission and are working for department 20.
D. Inserting into the table a new employee 10 who works for department 20 and earns a commission that is equal to the commission earned by employee 3.
E. Creating a table called COMMISSION that has the same structure and data as the columns EMP_ID and COMMISSIONS of the EMP table.
F. Decreasing the commission by 150 for the employees who are working in department 30 and earning a commission of more then 800.
第16题:
A.autoconn. And autoconf. Unavailable
B.commission file unavailableautoconn.
C.autoconf And commission files unavailable
D.Connected to NetAct不可用
第17题:
业务信道分配成功次数统计点是()消息
第18题:
1. public class Employee { 2. String name; 3. double baseSalary; 4. Employee(String name, double baseSalary) { 5. this.name = name; 6. this.baseSalary = baseSalary; 7. } 8. } And: 1. public class Salesperson extends Employee { 2. double commission; 3. public Salesperson(String name, double baseSalary, 4. double commission) { 5. // insert code here 6. } 7. } Which code, inserted at line 7, completes the Salesperson constructor?()
第19题:
在一个CS12.2k的呼叫过程中,IU口用户面的建立是在()
第20题:
The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?()
第21题:
You are developing the Payroll application that contains the SALARY and COMMISSION forms. When a user invoked the COMMISSION form from the SALARY form, the SAL value should be passed to the COMMISSION form. In which data form and at what time should you define the parameter to accept the value?()
第22题:
SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;
SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;
SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;
SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
第23题:
RAB ASSIGNMENT REQUEST之后;
RAB ASSIGNMENT RESPONSE之前;
RAB ASSIGNMENT REQUEST之前;
RAB ASSIGNMENT RESPONSE之后。