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CUSTOMER REFERRAL From: Bob SmithTo: Tompson Harris 10:12 AM, Monday, Dec. 21, 2015 Dear Mr. Harris, Thank you for your cooperation for our business in the recent years. With your great help and support, we have tripled our products in the last three year
题目
CUSTOMER REFERRAL From: Bob Smith< bobsmith@3>To: Tompson Harris 10:12 AM, Monday, Dec. 21, 2015 Dear Mr. Harris, Thank you for your cooperation for our business in the recent years. With your great help and support, we have tripled our products in the last three years. And the profits of our company increases steadily. Now, we have enlarged and consolidated our domestic market and European market. Next step we intend to explore the North American market, especially Canada’s and USA’s. However, we do not have good connections in this region. Therefore, we shall be very obliged if you could kindly introduce us to some of your reliable partners in North America who are interested in our products. We look forward to your early reply. Merry Christmas and Happy New Year! Yours sincerely, Bob Smith Project manager
1. How does Bob begin with his email()
A. With a self-introduction.
B. With his company’s current situation.
C. With presenting thanks for help and support.
2. What’s the current situation of Bob’s company()
A. Very good.
B. Not so good.
C. Just so so.
3. What are the market areas of Bob’s company()
A. Domestic and Asian market.
B. Domestic and North American market.
C. Domestic and European market.
4. What is the recent plan of Bob’s company()
A. To enlarge the domestic and European market.
B. To explore the North American market.
C. To withdraw from European market and strengthen the North American market.
5. What is the purpose of the email()
A. To give best wishes for the coming Christmas and New Year.
B. To ask for the introduction of some business partners in North America.
C. To consolidate the business relationship.
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更多“CUSTOMER REFERRAL From: Bob Smith < bobsmith@3> To: Tompson Harris 10:12 AM, Mo ”相关问题
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第1题：
Which statement accomplish this? ()A. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
B. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
C. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
D. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
E. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
F. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
参考答案：B
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第2题：
下述程序的输出结果是______。includemain(){enum team{Jack,Andy,Sam=10,Bob=Sam＋2,To 下述程序的输出结果是______。 #include＜stdio.h＞ main() { enum team{Jack,Andy,Sam=10,Bob=Sam+2,Tom}; printf("%d,%d",Andy,Tom); }
A．2，13
B．1，0
C．1，13
D．1，12
正确答案：C
解析：根据枚举型变量的定义方法，Jack=0，Andy=1，Sam=10，Bob=12，Tom=13。 -
第3题：
给客户拨打电话的最佳时间段是（）？
A．9:00am-11:30am 2:00am-5:00pm
B．8:00am-11:30am 1:00am-5:00pm
C．7:30am-11:30am 12:30am-5:00pm
D．9:00am-10:00am 2:00am-4:00pm
9:00am-11:30am 2:00am-5:00pm -
第4题：
You need to create a table named ORDERS that contain four columns:1. an ORDER_ID column of number data type2. aCUSTOMER_ID column of number data type3. an ORDER_STATUS column that contains a character data type4. aDATE_ORDERED column to contain the date the order was placed.When a row is inserted into the table, if no value is provided when the order was placed, today‘s date should be used instead.Which statement accomplishes this? （）
A. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
B. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
C. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
D. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
E. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
F. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
参考答案：E
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第5题：
试题六（共 15 分）阅读下列说明和 C++代码，填补代码中的空缺，将解答填入答题纸的对应栏内。【说明】以下 C++代码实现一个简单客户关系管理系统（CrM）中通过工厂（Customerfactory）对象来创建客户（Customer）对象的功能。客户分为创建成功的客户（realCustomer）和空客户（NullCustomer）。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图6-1 所示。
【C++代码】#include#include using namespace std； class Customer｛protected:string name；public:（1） boll isNil（）=0；（2） string getName（）=0；﹜； class realCustomer （3）｛public:realCustomer（string name）｛this->name=name；﹜bool isNil（）｛ return false；﹜string getName（）｛ return name；﹜﹜； class NullCustomer （4） ｛public:bool isNil（）｛ return true；﹜string getName（）｛ return 〝Not Available in Customer Database〞； ﹜﹜；class Customerfactory｛public:string names［3］=｛〝rob〞, 〝Joe〞,〝Julie〞﹜；public:Customer*getCustomer（string name）｛for （int i=0；i<3；i++）｛if （names［i］.（5） ）｛return new realCustomer（name）；﹜﹜return （6）；﹜﹜； class CrM｛public:void getCustomer（）｛Customerfactory*（7）；Customer*customer1=cf->getCustomer（〝rob〞）；Customer*customer2=cf->getCustomer（〝Bob〞）；Customer*customer3=cf->getCustomer（〝Julie〞）；Customer*customer4=cf->getCustomer（〝Laura〞）； cout<<〝Customers〞< 答案：解析：1)virtual2)virtual3):public Customer4):public Customer5)compare(name)==06)new Null Customer()7)cf=New CustomerFactory();
【解析】
本题考察使用C++代码实现实际问题。在C++中，动态绑定是通过虚函数来实现的。此题中用到了虚函数，所以要在成员函数原型缺钱加一个关键字virtual。类RealCustomer和类NullCustomer是类Customer的派生类，因此3、4空都填public Customer。进行对比数据库中的人名compare(name)==0第6空与前面语句是相反的，一个是返回new RealCustomer(name)，那么此处应填：new Null Customer()第7空，用工厂创建对象，cf=New CustomerFactory(); -
第6题：
10、若 Bob 给Alice发送一封邮件，并想让除Alice之外的人无法读懂邮件内容，则Bob应该选用（)对邮件加密。
A．Alice的公钥
B．Alice的私钥
C．Bob的公钥
D．Bob 的私钥
D