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参考答案:A
更多“—() — In most cases, it is the total income received. ”相关问题
  • 第1题:

    下面哪个语句不能完成1到10的累加功能, total初值为0。

    A.for i in range(10,0):total+=i

    B.for i in range(1,11):total+=i

    C.for i in range(10,0,-1):total+=i

    D.for i in (10,9,8,7,6,5,4,3,2,1):total+=i


    for i in range(10,0):sum+=i

  • 第2题:

    34、若要实现total=1+2+3+4+5求和,以下程序段错误的是()

    A.int i=1,total=1; while(i<5) { total+=i; i+=1; }

    B.int i=1,total=0; while(i<=5) { total+=i; i+=1; }

    C.int i=0,total=0; while(i<5) { i+=1; total+=i; }

    D.int i=0,total=0; while(i<=5) { total+=i; i+=1; }


    A

  • 第3题:

    【单选题】下面的个人所得税程序中,满足语句覆盖测试用例的输入数据是() if (income < 800) taxRate= 0; else if (income <= 1500) taxRate = 0.05 ; else if (income < 2000) taxRate = 0.08 ; else taxRate= 0.1 ;

    A.income = (800, 1500, 2000, 2001)

    B.income = (800, 801, 1999, 2000)

    C.income = (799, 1499, 2000, 2001)

    D.income = (799, 1500, 1999, 2000)


    D

  • 第4题:

    若要实现total=1+2+3+4+5求和,以下程序段错误的是()

    A.int i=1,total=1; while(i<5) { total+=i; i+=1; }

    B.int i=1,total=0; while(i<=5) { total+=i; i+=1; }

    C.int i=0,total=0; while(i<5) { i+=1; total+=i; }

    D.int i=0,total=0; while(i<=5) { total+=i; i+=1; }


    A

  • 第5题:

    对下面的计算个人所得税程序中,满足判定覆盖的测试用例是()。 if (income<800) taxrate=0; else if (income<=1500) taxrate=0.05; else if (income<2000) taxrate=0.08; else taxrate=0.1;

    A.income=(799, 1500, 1999, 2000)

    B.income=(799, 1501, 2000, 2001)

    C.income=(800, 1500, 2000, 2001)

    D.income=(800, 1499, 2000, 2001)


    A

  • 第6题:

    下列正确的求和语句是()

    A.total=1

    B.total+1

    C.total*1

    D.total by 1


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