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一____________?一I’v never been there but I hope to go there in the future.A .Where are you going for holidayB. Have you been to AmericaC. What did you do last week

题目

一____________?

一I’v never been there but I hope to go there in the future.

A .Where are you going for holiday

B. Have you been to America

C. What did you do last week


相似考题
参考答案和解析
参考答案:B
更多“一____________?一I’v never been there but I hope to go there in the future.A .Where are ”相关问题
  • 第1题:

    My sister has_____ been to the Summer Palace. I ’m going to take her there.

    A.ever

    B.sometime

    C.never


    参考答案:C

  • 第2题:

    光电法原子发射光谱分析中谱线强度是通过下列哪种关系进行检测的( I——光强,i——电流, V——电压)? ( )

    A.I →i →V

    B.i →V →I

    C.V →i →I

    D.I →V →i


    参考答案:A

  • 第3题:

    下列选项中,哪一组是正三和弦( )
    A.I、Ⅱ、Ⅲ级和弦
    B.I、Ⅳ、V级和弦
    C.I、Ⅲ、V级和弦
    D.I、Ⅳ、Ⅵ级和弦


    答案:B
    解析:
    正三和弦是指在调式的主音、下属音、属音(即Ⅰ、Ⅳ、Ⅴ级音)上构成的三和弦,分别代表着和声的三个功能(主功能、下属功能、属功能),是调式中最为重要的三个和弦。主功能用字母T表示,下属功能用字母S表示,属功能用字母D表示。

  • 第4题:

    If you _______ out to play, I _______ along with you.

    A.were, will go

    B.go, have been gone

    C.go, will go

    D.are going, am going


    参考答案:C

  • 第5题:

    大多数药物出现作用由快到慢的顺序为

    A.p.o.>i.h.>i.m.>i.v.

    B.i.h.>i.m.>i.v.>p.o.

    C.i.m.>i.v.>p.o.>i.h.

    D.i.v.>p.o.>i.h.>i.m.

    E.i.v.>i.m.>i.h.>p.o.


    正确答案:E

  • 第6题:

    如下程序实现对数组v按从大到小进行排序,请补充完善。 main() { int x,v[]={41,3,4,16,7,8,10,113,14},n=9; int i, j, k; for (i=0; i<n;i++) { k=i; for (j= i+1;j<n;j++) if (v[j]>v[k]) k=j; if(i!=k) { v[i] = v[i]+v[k]; 【1】 ; 【2】 ; } } for (i=0; i<n;i++) printf("%d ",v[i]); }


    #include<iostream> using namespace std; void sort( double x,double y ); void sort( double x,double y,double z ); int main() { sort( 5.6, 79 ); sort( 0.5, 30.8, 5.9 ); } void sort(double x,double y) { if ( x>y ) cout << x << '\t' << y << endl; else cout << y << '\t' << x << endl; } void sort( double x,double y,double z ) { double t; if( y<z ) { t = y; y = z; z = t; } if( x<z ) { t = x; x = z; z = t; } if( x<y ) { t = x; x = y ;y = t; } cout << x << '\t' << y << '\t' << z << '\t' << endl; }