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参考答案和解析
正确答案:C
自己式呼吸器的时间是最少30分钟。
更多“What is the minimum period of time that the air supply for a self-contained breathing appa ”相关问题
  • 第1题:

    在 Windows 中,运行( )命令得到下图所示结果。以下关于该结果的叙述中,错误的是( )。

    Pinging 59.74.111.8 with 32 bytes of data:

    Reply from 59.74.111.8: bytes=32 time=3ms TTL=60

    Reply from 59.74.111.8: bytes=32 time=5ms TTL=60

    Reply from 59.74.111.8: bytes=32 time=3ms TTL=60

    Reply from 59.74.111.8: bytes=32 time=5ms TTL=60

    Ping statistics for 59.74.111.8:

    Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),

    Approximate round trip times in milli-seconds:

    Minimum = 3ms, Maximum = 5ms, Average = 4ms

    A.ipconfig/all
    B.ping
    C.netstat
    D.nslookup

    答案:B
    解析:
    ping命令的作用的检查两个机器之间的连通性的。

  • 第2题:

    8、基于initial语句产生普通时钟信号, parameter clk_period = 10; reg clk; initial begin clk = 0; ________________; end

    A.always #(clk_period/2) clk = ~clk

    B.forever #(clk_period/2) clk = ~clk

    C.always #(clk_period) clk = ~clk

    D.forever #(clk_period) clk = ~clk


    always #(clk_period/2) clk = ~clk;forever #(clk_period/2) clk = ~clk

  • 第3题:

    在端口PHI1创建时钟周期为10,上升在5.0,下降在9.5

    A.create_clock “PHI1” –period 10 –waveform {5.0 9.5}

    B.create_clock “PHI1” period 10 –waveform {5.0 9.5}

    C.create_clock “PHI1” period 10 waveform {5.0 9.5}

    D.create_clock “PHI1” –period 10 –waveform {1 2}


    create_clock “PHI1” –period 10 –waveform {5.0 9.5}

  • 第4题:

    在 Windows 中,运行(请作答此空)命令得到下图所示结果。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds:Minimum = 3ms, Maximum = 5ms, Average = 4ms)

    A.ipconfig/all
    B.ping
    C.netstat
    D.nslookup

    答案:B
    解析:
    ping命令的作用的检查两个机器之间的连通性的。

  • 第5题:

    基于initial语句产生普通时钟信号, parameter clk_period = 10; reg clk; initial begin clk = 0; ________________; end

    A.always #(clk_period/2) clk = ~clk

    B.forever #(clk_period/2) clk = ~clk

    C.always #(clk_period) clk = ~clk

    D.forever #(clk_period) clk = ~clk


    always #(clk_period/2) clk = ~clk;forever #(clk_period/2) clk = ~clk

  • 第6题:

    以下关于VDB函数的语法正确的是()。

    A.VDB(cost,salvage,life,period,factor)

    B.VDB(cost,salvage,life,period,month)

    C.VDB(cost,salvage,life,per)

    D.VDB(cost,salvage,life,start-period,end-period,factor,no-switch)


    VDB(cost,salvage,life,start-period,end-period,factor,no-switch)