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They will take measures against (海盗)___and pilferageA.privatesB.piratesC.stowawayD.personnel

题目

They will take measures against (海盗)___and pilferage

A.privates

B.pirates

C.stowaway

D.personnel


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更多“They will take measures against (海盗)___and pilferageA.privatesB.piratesC.stowawayD.perso ”相关问题
  • 第1题:

    We have lodged a claim () ABC & Co.() the quality of the goods shipped()m.v. “Peace”.

    A、against, for, by

    B、with, for, under

    C、on, against, as per

    D、to, for, per


    参考答案:A

  • 第2题:

    [A] in [B] with [C] against [D] for


    正确答案:B

  • 第3题:

    惩罚性措施:__________ measures


    采取措施

  • 第4题:

    海盗登船时,主要靠___的掩护。

    A.海盗本人

    B.海盗船上其他人

    C.海盗本人及海盗船上其他人


    正确答案:B

  • 第5题:

    Most of the meeting was spent going over the salesfrom the previous month.

    A.shapes
    B.celebrities
    C.figures
    D.measures

    答案:C
    解析:
    和空格前的sales相关的为数字,因此figures放在空格处最恰当。要把sales figures当做一个整体来记忆。

  • 第6题:

    1、利用艾拉托斯特尼筛法无穷素数列表primes (参见讲义第8章) 获得介于100000和200000之间素数的方法是

    A.take 200000 (take 100000 primes)

    B.take 100000 (take 200000 primes)

    C.take 100000 (drop 100000 primes)

    D.takeWhile (\x -> x <= 200000) (dropWhile (\x -> x <= 100000) primes)

    E.takeWhile (\x -> x <= 200000) (take 200000 primes)

    F.[x | x <- primes, x >100000, x < 200000]

    G.[x | x <- take 200000 primes, x >100000, x < 200000]


    Sieve(n,P). 输入:正整数n. 输出:小于等于n的所有素数P. ①if n=1 then P← ,计算结束; ②P←{2}; ③a←2; ④if n=a then计算结束; ⑤b←min{a 2 ,n}; ⑥Q←{x|a<x≤b}; ⑦for P中的每一个x ⑧for Q中的每一个y ⑨ then从Q中删去y; ⑩P←P∪Q; (11)a←b; (12)转④.