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更多“ACPI为PC机主机定义了6种不同的能耗状态(S0~S5),S0为正常工作状态。S1~S3为睡眠状态,S4为休眠状态 ”相关问题
  • 第1题:

    下列关于5状态的状态机说明部分的程序是否正确 parameter [2:0] s0=0, s1=1,s2=2,s3=3,s4=4; reg [2:0] current_state, next_state;


    用状态观测器的估计值反馈比用状态变量反馈相当于多了一个扰动量的作用;用状态观测器的估计值反馈和用状态变量反馈稳定性一样;用状态观测器的估计值反馈和用状态变量反馈稳态性能一样;带有状态观测器的状态反馈系统的设计中状态观测器的设计和状态反馈的设计是互不影响的

  • 第2题:

    下述程序中能够实现安全状态机设计的是

    A.Parameter s0=0,s1=1,s2=2,s3=3,s4=4,s5=5,s6=6,s7=7; ... s5: next_state =s0; S6: next_state =s0; S7: next_state =s0; default:begin next_state =s0;#B.define s0=1,s1=2,s2=4,s3=4,s4=8 s5: next_state =s1; S6: next_state =s1; S7: next_state =s2; default:begin next_state =s0;#C.Parameter s0=40,s1=41,s2=42,s3=43,s4=44,s5=45,s6=46,s7=47; ... s5: next_state =s0; S6: next_state =s0; S7: next_state =s0;#D.以上都是正确选型
    Parameter s0=0,s1=1,s2=2,s3=3,s4=4,s5=5,s6=6,s7=7; ... s5: next_state =s0; S6: next_state =s0; S7: next_state =s0; default:begin next_state =s0;;define s0=1,s1=2,s2=4,s3=4,s4=8 s5: next_state =s1; S6: next_state =s1; S7: next_state =s2; default:begin next_state =s0;

  • 第3题:

    11、已知如下对输出逻辑的描述代码,state为当前状态,out为状态机输出。由此可知该状态机为Mealy型状态机。 always @(state) case (state) S0: out = 0; S1: out = 0; S2: out = 1; S3: out = 1; endcase


    错误

  • 第4题:

    计算机ACPI全局电源管理状态包括()

    A.正常工作

    B.睡眠状态

    C.休眠状态

    D.软关机状态


    IPCA功能

  • 第5题:

    下列Moore型状态机采用Verilog语言说明部分正确的是:

    A.parameter [2:0] s0=0, s1=1,s2=2,s3=3,s4=4; reg [2:0] current_state, next_state;

    B.parameter [1:0] s0=0, s1=1,s2=2,s3=3,s4=4; reg [1:0] current_state, next_state;

    C.TYPE FSM_ST IS (s0, s1,s2,s3,s4); SIGNAL current_state, next_state: FSM_ST;

    D.typedef enum {s0, s1,s2,s3,s4} type_user; type_user current_state, next_state


    parameter [2:0] s0=0, s1=1,s2=2,s3=3,s4=4; reg [2:0] current_state, next_state;