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( ) :refers to the application of the internet and other informatio technology inconventional industries.It is an incomplete equation where various Internets (mobile Internet,cloud computing,big data or Internet of things) can be added to other fileds, fo

题目

( ) :refers to the application of the internet and other informatio technology inconventional industries.It is an incomplete equation where various Internets (mobile Internet,cloud computing,big data or Internet of things) can be added to other fileds, fostering new industries and business development.

A.internet plus

B.industry 4.0

C.Big data

D.Cloud computing


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参考答案和解析
正确答案:A
更多“( ) :refers to the application of the internet and other informatio technology inconve ”相关问题
  • 第1题:

    假设现在已经利用Application对象把变量a赋值为456,那么下列语句中能显示出“456”的是______。

    A.<%=Application"a"%>

    B.<%=Application("a")%>

    C.<%=Application(a)%>

    D.<%=Application:a%>


    正确答案:B

  • 第2题:

    创意产业的3T理论是指的哪3T?

    A.Technology, Talent, Tolerance

    B.Technology, Talent, Taste

    C.Technology, Taste, Tolerance

    D.Technology, Talent, Time


    Technology, Talent, Tolerance

  • 第3题:

    下面的语法格式中,()是将一个值保存到application变量中。

    A.Application.setAttribute(“变量名称”,值);

    B.Application.getAttribute(“变量名”);

    C.Application.getRealPath(“/”)%

    D.Application.getRealPath(“变量名”);


    Application.setAttribute(“变量名称”,值);

  • 第4题:

    针对下列程序段,需要( )个测试用例才可以满足语句覆盖的要求。
    switch(value){case 0:other=30;break;case 1:other=50;break;case 2:other=300;case 3:other=other/value;break;default:other=other*value;}

    A.2
    B.3
    C.4
    D.5

    答案:C
    解析:
    本题考查白盒测试用例设计方法--语句覆盖法的概念。语句覆盖(Statement Coverage)的含义是:选择足够多的测试数据,使被测程序中的每条语句至少执行一次。

  • 第5题:

    1、针对下列程序段,需要()个测试用例才可以满足语句覆盖的要求。 switch (value ) { case 0: other = 30; break; case 1: other = 50; break; case 2: other = 300; case 3: other = other/value; break; default: other = other * value; }

    A.2

    B.3

    C.4

    D.5


    4

  • 第6题:

    下面代码实现一个站点访问量计数器,空白处的代码为()。 void ____________(object sender, EventArgs e) { Application.Lock(); Application["AccessCount"] = (int)Application["AccessCount"] + 1; Application.UnLock(); }

    A.Application_Start

    B.Application_Error

    C.Session_Start

    D.Session_End


    C