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I want to learn() about the industry so that I'm better prepared.A、possible ofB、as much as possibleC、as possible muchD、as possible as much

题目
I want to learn() about the industry so that I'm better prepared.

A、possible of

B、as much as possible

C、as possible much

D、as possible as much

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更多“I want to learn() about the industry so that I'm better prepared. ”相关问题

  • 第1题：

    I______to be a scientist when I______ a boy.

    A、wanted, was

    B、want, am

    C、wanted, am

    D、want, was


    正确答案：A

  • 第2题：

    下面游离SO2直接碘滴定法的原理叙述不正确的是( )。

    A.I2与SO2发生氧化还原反应

    B.I2被氧化成I-

    C.SO2被氧化成SO2-4

    D.微过量的I2遇淀粉产生兰色为终点


    正确答案：B

  • 第3题：

    下面（）仅输出m的大于1的最小因子。

    A．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); break; }

    B．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); continue; }

    C．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); }

    D．i=2; while (m % i != 0) i++; printf("%d is 最小因子n", i);


    A

  • 第4题：

    下面程序输出的结果是()。includeusing namespace std;void main(){ char ch[][8]={"g

    下面程序输出的结果是( )。 #include＜iostream＞ using namespace std; void main() { char ch[][8]={"good","better","best"}; for(int i=1;i＜3;++i) { cout＜＜ch[i]＜＜endl； } }

    A．good better

    B．better best

    C．good best

    D．good


    正确答案：B
    解析：二维数组ch共3行8列，for循环语句输出第2、3行的数组元素

  • 第5题：

    I’m not fully aware ______ what happened at the loading port．

    A.at

    B.to

    C.of

    D.about


    正确答案：C

  • 第6题：

    下面（）是正确的判断素数程序（m＞1)。

    A．j=0; for (i =2; i＜=m-1; i++) if (m % i != 0) j++; if(j==m-2) printf(“%d是素数n", m);

    B．j=0; for (i =2; i＜=m-1; i++) if (m % i == 0) j++; if(j==0) printf(“%d是素数n", m);

    C．flag=0; for (i =2; i＜=m-1; i++) if (m % i == 0) flag=1; if(flag==0) printf(“%d是素数n", m);

    D．for (i =2; i＜=m-1; i++) if (m % i == 0) i=m+2; if(i==m+3) printf(“%d是素数n", m);


    D

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