I like to get up early so that I can get plenty of work ________.
A. to do
B. doing
C. done
D. being done
第1题:
此题为判断题(对,错)。
第2题:
A.for(inti=0;i<a.size();i++) System.out.println(a.get(i)));
B.for(inti=0;i<a.size();i++) System.out.println(a[i]);
C.while(iter.hasNext()) System.out.println(iter.next());
D.for(inti=0,i<a.size();i++) System.out.println(iter[i]);
E.for(inti=0;i<a.size();i++) System.out.println(iter.get(i));
第3题:
By the time l_________ (get) up,my mother _________ (get) the breakfast ready.
第4题:
A:I prefer watching TV. B:So( ) I.
A. have
B. am
C. do
第5题:
____________prevent a lot of radiation damage
[A] get
[B] make
[C] have
[D] do
是完型填空吧?你要把整篇都传上来这样片面的截句无法给出答案。
第6题:
下面的代码用于输出字符数组ch中每个字符出现的次数,应该填入的代码是()public static void main(String[] args) { char[] ch = { 'a', 'c', 'a', 'b', 'c', 'b' }; HashMap map = new HashMap(); for (int i = 0; i < ch.length; i++) { < 填入代码 > } System.out.println(map); }
A.if (map.contains(ch[i])) { map.put(ch[i], map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
B.if (map.contains(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
C.if (map.containsKey(ch[i])) { map.put(ch[i], (int) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
D.if (map.containsKey(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }