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更多“The analysis of the first shipment is not ( ). ”相关问题
  • 第1题:

    The stages within the development phase of the software life cycle are ( 71 ).

    A.design, analysis, implementation, and testing

    B.analysis, design, implementation, and testing

    C.analysis, design, testing, and implementation

    D.design, analysis, testing, and implementation


    正确答案:C

  • 第2题:

    The stages within the development phase of the software life cycle are( ).
    软件生命周期开发阶段的阶段是

    A.design,analysis,implementation,and testing
    设计、分析、实现和测试
    B.analysis,design,implementation,and testing
    分析、设计、实现和测试
    C.analysis,design,testing,and implementation
    分析、设计、测试和实现
    D.design,analysis,testing,and implementation
    设计、分析、测试和实现

    答案:B
    解析:
    属于软件生命周期中开发阶段的是分析、设计、实施和测试。

  • 第3题:

    在循环单链表中,设指针first指向头结点,当_____时表示链表为空。

    A.first==NULL

    B.first->link==NULL

    C.first->link==first

    D.first->link->link==first


    first==NULL

  • 第4题:

    PART Ⅰ: INCOMPLETE SENTENCES
    Directions: This part of the test has incomplete sentences. Four words or phrases, marked (A), (B), (C), (D), are given beneath each sentence. You are to choose the one word or phrase that best completes the sentence. Then, on your answer sheet, find the number of the question and mark your answer.
    1. Food products containing chocolate are subject to a ______ of up to 35 percent when imported to Japan.

    A. test
    B. tariff
    C. souvenir
    D. shipment

    答案:A
    解析:
    be subject to表示"接受,经受";test有"检验,化验"的意思;tariff表示"关税,价目表";souvenir表示"纪念品";shipment表示 "船运,货物"。因此,A项符合题意,句子的意思是:出口到日本的含有巧克力的食品中有35%要接受检验。

  • 第5题:

    Bloomfield introduced the IC analysis, whose full name is ( ) Analysis.

    A.Internal Component
    B.Innate Capacity
    C.Internal Constituent
    D.Immediate Constituents

    答案:D
    解析:
    考查语义知识。IC的完整名字是Immediate constituents,意为“直接成分分析法”,最先由Bloomfield在《语言论》中提出。

  • 第6题:

    带头结点的单链表first为空的判定条件是:

    A.first == NULL;

    B.first->link == NULL;

    C.first->link == first;

    D.first != NULL;


    first->next==NULL;