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参考答案和解析
参考答案:B
更多“A week ago, I sent him a statement()the amount overdue.A.showB. showingC. showed ”相关问题
  • 第1题:

    If I had come here yesterday, I _______him.

    A. would have seen

    B. would see

    C. have seen

    D. saw


    正确答案:A

  • 第2题:

    有下列程序:includeUsing namespace std;Class Amount{ int amount;public; Amount(i

    有下列程序: #include<iostream> Using namespace std; Class Amount{ int amount; public; Amount(int n=O):amount(n){} Int getAmount()const{return amount;} Amount &operator+=(AmountA) {

    A.*this

    B.this

    C.&amount

    D.amount


    正确答案:D
    解析: 此题考查的是“+”运算符重载和this指针。语句amount+=a.amount;实现3和7的求和,得到amount=10,要使程序的输出结果为10,需要把amount的值作为函数的返回值,所以横线处应填入amot。

  • 第3题:

    下述代码中,statement应该如何写才能使得程序输出1 int t = 1; try { ...... throw t; ...... } catch (statement ) { cout << i; }

    A.int i

    B.float i

    C.unsigned int i

    D.exception i


    int i

  • 第4题:

    以下程序的输出结果是 ( ) enum weekday {sun=7,mon=1,tue,wed,thu,fri,sat}; main( ) { enum weekday workday,week_end; int i,a [8]; workday=tue; week end=sun; pritnf("\ntuesday=%d sunday=%d", wotkday, week_end); workday=sun+tue; week_end=(enum weekday)3; printf ("tuesday=%d sunday=%d", workday week_end); a[sun]=sun; a[mon]=mon a[tue]=tue; a[wed]=wed; a[thu]=thu; a[fri]=fr; a[sat]=sat; for(i=1;i<7;i+ +) printf("%d",a [i]); }

    A.tuesday=2 sunday=7;tuesday=2 sunday=7;1 2 3 4 5 6 7

    B.tuesday=2 sunday=7;tuesday=9 sunday=3;1 2 3 4 5 6 7

    C.tuesday=0 sunday=7;tuesday=2 sunday=3;1 2 3 4 5 6 7

    D.tuesday=1 sunday=2;tuesday=3 sunday=4;1 2 3 4 5 6 7


    正确答案:B

  • 第5题:

    Calendar的静态字段表示一年中的第几周的是()。

    A.WEEK_OF_YEAR

    B.DAY_OF_YEAR

    C.WEEK_OF_MONTH

    D.DAY_OF_WEEK


    WEEK_OF_YEAR

  • 第6题:

    1、下述代码中,statement应该如何写才能使得程序输出1 int t = 1; try { ...... throw t; ...... } catch (statement ) { cout << i; }

    A.int i

    B.float i

    C.unsigned int i

    D.exception i


    int i