niusouti.com

I had two jobs growing up and they all helped shape my life. When I was about 12, I started caddying (当球童) at a nearby country club. All the kids in the neighborhood did it, and I liked it a lot. I go to watch people who were generally pretty wealthy. The

题目

I had two jobs growing up and they all helped shape my life. When I was about 12, I started caddying (当球童) at a nearby country club. All the kids in the neighborhood did it, and I liked it a lot. I go to watch people who were generally pretty wealthy. They were businessmen and doctors. I would listen to them talking about things and see how they behaved with each other. It was like a fly on the wall at a meeting. The second job was at a shoe store. I constantly met people from all walks of life and the challenge was exciting. I'd start bringing them different kinds of shoes and get right down there and put them on their feet. If they didn't like a certain shoe, I always tried to be thinking ahead to a pair they might like better. It was like stepping up to the plate in a baseball game. Every time someone walked into that store, I was going to bat and taking a swing. I never wanted to let a customer get out of that store without buying a pair of shoes to his satisfaction. This job helped teach me an important business lesson: You have to take risks in business. If you take a risk and fail, get up to bat and swing again.

1). The author thinks what he has learned from his first job is ().

2). The phrase "people from all walks of life" in the third paragraph means people ().

3). The author thinks his second job is ().

4). The author compares his second job to ().

5). The business lesson the author gets from selling shoes is ().

(1).A、how to learn to like a job

B、how to talk and behave properly

C、how to become wealthy

D、how to listen to people

(2).A、walking in different ways

B、having different interests in life

C、coming from different parts of the city

D、working in different occupations

(3).A、challenging

B、important

C、different

D、satisfying

(4).A、a fly on the wall at a meeting

B、stepping into a golf course

C、joining a baseball game

D、taking a bat to swing

(5).A、thinking ahead of the customers

B、trying every possible way to satisfy a customer

C、never be afraid of taking risks

D、never let go anyone walking into the shop

相似考题

1.（ 10 ）执行下列程序，显示的结果是 【 10 】 。one= "WORK"two = ""a = LEN ( one )i = aDO WHILE i>=1two = two + SUBSTR ( one ,i , 1 ）i=i - 1ENDDO? two

2.I _______ him study hard until he passes the exam.A.askB.madeC.letD.had

3.If he had asked me, I ( ) him.A.should have helpedB.would helpC.would have helpedD.helped

4.I _____my breakfast at 8, but_____ I lunch yet. .A. had, haven't hadB. had, didn't haveC. have had, didn't have

更多“I had two jobs growing up and they all helped shape my life. When I was about 12, I st ”相关问题

  • 第1题：

    执行下列程序，显示的结果是【 】。

    ne="WORK"

    two=""

    a=LEN(one)

    i=a

    DO WHILE i＞=l

    two=two+SUBSTR(one,i, 1)

    i=i-1

    ENDDO

    ?two


    正确答案：KROW
    KROW 解析：DO WHILE—ENDDO语句格式：
    DO WHILE条件＞
    语句序列1＞
    [LOOP]
    语句序列2＞
    [EXIT]
    语句序列3＞
    ENDDO
    执行该语句时，先判断DO WHILE处的循环条件是否成立，如果条件为真，则执行DO WHILE与ENDDO之间的命令序列(循环体)。当执行到ENDDO时，返回到DO WHILE，再次判断循环条件是否为真，以确定是否再次执行循环体。若条件为假，则结束该循环语句，执行ENDDO后面的语句。
    而常用函数中：LEN(字符表达式)：返回一个字符串的长度，返回值是数值型。
    SUBSTR(字符表达式，起点位置[,长度])：在一个字符串中，从指定位置起返回给定长度的子串，返回值是字符型。

  • 第2题：

    按行优先顺序存储下三角矩阵的非零元素，则计算非零元素a/sub>ij1≤j≤i≤n)的地址的公式为

    A．LOC(aij)=LOC(all)+i×(i+1)/2+j

    B．LOC(aij)=LOC(all)+i×(i+1)/2+(j-1)

    C．LOC(aij)=LOC(all)+i×(i-1)/2+j

    D．LOC(aij)=LOC(all)+i×(i-1)/2+(j-1)


    正确答案：D
    解析：通过运算可以得出结论选项D)正确。

  • 第3题：

    3.—Mr Zhang，I'm not feeling well． I-d like to have this afternoon _________ to go to a doctor．

    —OK．

    A．on

    B．off

    C．down

    D．up


    正确答案：B
    3．B【解析】off作副词时可以表示“休假”。

  • 第4题：

    按行优先顺序存储下三角矩阵的非零元素，则计算非零元素aij（1≤j≤i≤n）的地址的公式为（ ）。 A．LOC(aij)＝LOC(a11）+i×(i+1）／2+j B．LOC(aij)＝LOC(all）＋i×(i＋1）／2+（j－1） C．LOC(aij)＝LOC(all）＋i×(i－1）／2+（j＋1） D．LOC(aij)＝LOC(all）＋i×(i－1）／2+（j－1）


    正确答案：D
    LOC(aij)＝LOC(all）＋i×(i－1）／2+（j－1）

  • 第5题：

    下面vb6.0中tagname,name,value有什么区别呀?

    webbrowser1.document.all(i).tagname

     webbrowser1.document.all(i).name

     webbrowser1.document.all(i).value


    比如document.all(i)是<input type="text" value="abcd" name="t1"/>那么这里tagname就是inputname就是t1value就是abcd,他们都是该元素的属性，如果不存在该属性那么你在引用的时候就会出现错误。
    比如document.all(i)是<input type="text" value="abcd" name="t1"/>
    那么这里tagname就是input
    name就是t1
    value就是abcd,他们都是该元素的属性，如果不存在该属性那么你在引用的时候就会出现错误。

  • 第6题：

    简述下列算法的执行步骤和功能。 void fun（int a[],int n) { int i=0,e; SqStack *st; InitStack（st); for（i=0;i＜n;i++) Push（st,a[i]); i=0; while（!StackEmpty（st)) { Pop（st,e); a[i++]=e; } DestroyStack（st); }


    1. Q=( ) Q 1 =(1029) Q 2 =(-5-4-6)2.将队列Q的元素依次退队并将正值及0元素入队到Q 1 负值元素入队到Q 2 。 1. Q=( ) Q 1 =(1,0,2,9) Q 2 =(-5,-4,-6)2.将队列Q的元素依次退队，并将正值及0元素入队到Q 1 ，负值元素入队到Q 2 。

相关内容