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They've won their last three matches,_________I find a bit surprising.A．thatB．whenC．whatD．which

题目

They've won their last three matches,_________I find a bit surprising.

A．that

B．when

C．what

D．which

相似考题

1.－ ____________________________－ Won't you have another coffee?A.Thank you very much for a wonderful partyB.I'm glad to have met you.C.Thanks for all your hospitality.D.Sorry, it's time I left now.

2.I’ll go for a walk with you if it ____ tomorrow.A. won’t rainB. doesn’t rainC. will rainD. not rains

3.—Sorry, I have kept you waiting. —__________________ .A.That’s all rightB.I don’t careC.I’m sadD.No, not at all

4.to, I, how, last, winter, skate, learned__________________________________________________________________________.

更多“They've won their last three matches,_________I find a bit surprising. A.that ”相关问题

  • 第1题：

    i’d rather you__________those important documents with you.

    A. won’t take

    B. didn’t take

    C. not take

    D. don’t take


    参考答案：B

  • 第2题：

    下列______不是Matcher类的方法。

    A．find()

    B．matches()

    C．start()

    D．matcher()


    正确答案：D

  • 第3题：

    2、在顺序结构表示的线性表中，删除第i个元素（数组下标为i-1)，需要把后面的所有元素都往前挪一位，相应的语句是： for （___________ ) PtrL-＞Data[j-1]=PtrL-＞Data[j]; 其中空缺部分的内容应该是

    A．j = i; j＜ = PtrL-＞Last; j++

    B．j =PtrL-＞Last; j＞= i; j--

    C．j = i-1; j＜ = PtrL-＞Last; j++

    D．j =PtrL-＞Last; j＞= i-1; j--


    O(n)

  • 第4题：

    You' ll tell John about that, won’t you ? -Yes, I'll tell him about it as soon as he( ).

    A. will wake up

    B. wakes up

    C. is waking up

    D. woke up


    正确答案：C

  • 第5题：

    25． —I'm afraid the meeting has begun．

    —Don't worry． It _________ ． until the bell _________．

    A． doesn't begin; rings

    B． won't begin; will ring

    C． won't begin; rings

    D． doesn't begin; will ring


    正确答案：C
    25．C【解析】not．．． until．．．意为“直到……才……”，主句用一般将来时，从句要用一般现在时。故选C。

  • 第6题：

    在顺序结构表示的线性表中，删除第i个元素（数组下标为i-1)，需要把后面的所有元素都往前挪一位，相应的语句是： for （___________ ) PtrL-＞Data[j-1]=PtrL-＞Data[j]; 其中空缺部分的内容应该是

    A．j = i; j＜ = PtrL-＞Last; j++

    B．j =PtrL-＞Last; j＞= i; j--

    C．j = i-1; j＜ = PtrL-＞Last; j++

    D．j =PtrL-＞Last; j＞= i-1; j--


    O(n)

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