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Personal firewall is a technology that helps(66)intruders from accessing data on your PC via the Internet or another network, by keeping(67)data from entering or exiting your system.Hackers do not just target national security organizations for(68): They

题目

Personal firewall is a technology that helps(66)intruders from accessing data on your PC via the Internet or another network, by keeping(67)data from entering or exiting your system.

Hackers do not just target national security organizations for(68): They want your tax returns, network passwords, or bank account numbers. And you do not want the FBI kicking in your door because someone hijacked your PC to(69)in the latest denial-of-service attack on the Internet. Now that "always-on" broadband connections such as cable modems and digital subscriber line are becoming more popular, home users are at risk. Fortunately, you can protect your data. Firewalls can block(70)attacks and protect your PC from outside threats.

A．allow

B．prevent

C．invite

D．get

相似考题

1.Does he often _______ his mother ______ the room?A.help, cleansB.help,cleanC.helps, cleaningD.helps, clean

2.Each person takes his plate, helps ____ and comes back to his place.A: himB: themC: hisD: himself

3.What's ( )job? Are ( ) British?A. your, yourB. you, yourC. your, you

4.)16．A．makesB．letsC．improvesD．helps

更多“Personal firewall is a technology that helps(66)intruders from accessing data on your PC v ”相关问题

  • 第1题：

    下列程序的运行结果是【 】。 include class SomeClass { public: SomeClass(int va

    下列程序的运行结果是【 】。

    include ＜iostream. h＞

    class SomeClass

    {

    public:

    SomeClass(int value) { some_value=value;};

    void show_data(void) { cout＜＜data＜＜"＜＜~some_value＜＜endl; };

    static void set_data(int value) {data=value; }

    private:

    static int data;

    int some_value

    };

    int SomeClass::data

    void main(void)

    {

    SomeClass my_class(1001),your_class(2002);

    your_class. set_data(4004);

    my_elass. show_data()

    }


    正确答案：4004 1001
    4004 1001 解析：本题考查静态成员变量在不同对象间的共享现象。无论哪个对象修改了其静态变量的值，其他对象再访问该变量时已经发生了变化。

  • 第2题：

    Giventheconfigurationshownintheexhibit，whichconfigurationobjectwouldbeusedtoassociatebothNancyandWalterwithfirewalluserauthenticationwithinasecuritypolicy？（）profileftp-users{clientnancy{firewall-user{password"$9$lJ8vLNdVYZUHKMi.PfzFcyrvX7"；SECRET-DATA}}clientwalter{firewall-user{password"$9$a1UqfTQnApB36pBREKv4aJUk.5QF"；SECRET-DATA}}session-options{client-groupftp-group；}}firewall-authentication{pass-through{default-profileftp-users；ftp{banner{login"JUNOSRocks!"；}}}}

    A.ftp-group

    B.ftp-users

    C.firewall-user

    D.nancyandwalter


    参考答案：A

  • 第3题：

    重新加载防火墙的命令是（）。

    A．firewall-cmd --start

    B．firewall-cmd --reload

    C．firewall-start --reload

    D．firewall-cmd --enable


    firewall-cmd --reload

  • 第4题：

    Whichdatadictionaryviewsdisplaystheerrorinformationrelatedtoadatafile,whenaninternalreadfailsonthatfile?()

    A.V$DATAFILE

    B.V$DATAFILE_HEADER

    C.DBA_DATA_FILES

    D.V$DBFILE

    E.V$DATAFILE_ERRORS


    参考答案：B

  • 第5题：

    编写算法实现从邻接表中取出某个顶点V的存储位置。 intLocateVex（ALGraph& G,VertexType v) { int i=0; while（______&&i＜G.vernum) i++; if（G.vertices[i].data==v) return i; else return -1; }

    A．G.vertices[i++].data!=v

    B．G.vertices[i].data!=v

    C．G.vertices[i].data==v

    D．G.vertices[++i].data!=v


    B

  • 第6题：

    下列对称型错误的是

    A．L66P

    B．L6PC

    C．L66L2

    D．L66L26PC


    Pentium Ⅳ也采用了PentiumPro微处理器的P6微架构

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