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139 The initial cost of a product and the product's operation and maintenance costs _____ .A. increases perceived value when balanced.B. are incidental to each other because initial costs are "sunk"C. decreases design costs as operation periods increaseD.

题目

139 The initial cost of a product and the product's operation and maintenance costs _____ .

A. increases perceived value when balanced.

B. are incidental to each other because initial costs are "sunk"

C. decreases design costs as operation periods increase

D. provides perceived function value and product social dysfunction

E. are integrally related with each other because initial costs are "sunk"


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  • 第1题:

    已知程序如下,该程序实现的功能为_____。 (10) main() (20) { int counter; (30) ... //输入N值的语句,假设N为偶数,略 (40) long product = 1; (50) for counter = 1 to N step 2 (60) { product = product * counter; } (70) return product; (80) }

    A.product = 1*3*5*...* (N-1)

    B.product = 1*2*3*...*(N-1)

    C.product = 1+ 2+3+...+ (N-1)

    D.product = 1+3+5+...+(N-1)


    sum = 1!+2!+...+n!

  • 第2题:

    已知程序如下,该程序实现的功能为_____。 (10) main() (20) { int counter; (30) ... //输入N值的语句,略 (40) long product = 1; (50) for counter = 1 to N step 2 (60) { product = product * counter; } (70) return product; (80) }

    A.product = 1*2*3*...*(N-1)

    B.product = 1+ 2+3+...+ (N-1)

    C.product = 1*3*5*...* (N-1)

    D.product = 1+3+5+...+(N-1)


    product = 1*3*5*...* (N-1)

  • 第3题:

    33、已知程序如下,该程序实现的功能为_____。 (10) main() (20) { int counter; (30) ... //输入N值的语句,略 (40) long product = 1; (50) for counter = 1 to N step 2 (60) { product = product * counter; } (70) return product; (80) }

    A.product = 1*2*3*...*(N-1)

    B.product = 1+ 2+3+...+ (N-1)

    C.product = 1*3*5*...* (N-1)

    D.product = 1+3+5+...+(N-1)


    product = 1*3*5*...* (N-1)

  • 第4题:

    41、已知程序如下,该程序实现的功能为_____。 (10) main() (20) { int counter; (30) ... //输入N值的语句,略 (40) long product = 1; (50) for counter = 1 to N step 2 (60) { product = product * counter; } (70) return product; (80) }

    A.product = 1*3*5*...* (N-1)

    B.product = 1*2*3*...*(N-1)

    C.product = 1+ 2+3+...+ (N-1)

    D.product = 1+3+5+...+(N-1)


    product = 1*3*5*...* (N-1)

  • 第5题:

    如下程序用来计算公式1!+2!+3!+…+10!,请完善程序。 #include <iostream> using namespace std; int main() { int i,j,sum,product; cout<<"1!+2!+3!+.......+10!= "; sum=【1】; for (【2】) { product=【3】; for (【4】) { product*=j; } sum+=product; } cout<<sum<<endl; return 0; }


    40

  • 第6题:

    6、已知程序如下,该程序实现的功能为_____。 (10) main() (20) { int counter; (30) ... //输入N值的语句,略 (40) long product = 1; (50) for counter = 1 to N step 2 (60) { product = product * counter; } (70) return product; (80) }

    A.product = 1*2*3*...*(N-1)

    B.product = 1+ 2+3+...+ (N-1)

    C.product = 1*3*5*...* (N-1)

    D.product = 1+3+5+...+(N-1)


    sum = 1!+2!+...+n!